Golden State Warriors’ Draymond Green (25) grabs a rebound as Stephen Curry, third from left, boxes out Houston Rockets’ Dillon Brooks (9) during the first half of Game 1 of an NBA basketball first-round playoff series in Houston, Sunday, April 20, 2025. (Scott Strazzante/San Francisco Chronicle via AP)

Draymond Green of the Golden State Warriors is this season’s winner of the NBA Hustle Award, the league announced Friday. The award has been presented since 2017.

The Warriors forward was announced on Friday as winner of the 2024-25 NBA Hustle Award. The award, which was first given out in 2016-17, “honors players who make the effort plays that don’t often appear in the traditional box score but impact winning on a nightly basis,” according to the NBA.